Mekanika Teknik ( Statis Tertentu ) Part 2
GuruSipil - 23 February 2018Menghitung Momen, Gaya Lintang Balok yang Ditumpu oleh Dua Tumpuan
Beban Terpusat
Suatu Balok yang ditumpu oleh dua tumpuan yang panjangnya ( L = 10 meter ). Pada pertengahan balok bekerja gaya terpusat P = 5 t. Gambarlah bidang momen dan Gaya lintangnya.
Penyelesaian :
1. Carilah terlebih dahulu reaksi A dan B sebagai berikut :
∑MB = 0
RA.10 – P (5) = 0
RA.10 – 5 (5) = 0
RA . 10 = 25
RA = 25/10
RA = 2,5 ton
∑ V = 0
RA – P + RB = 0
2,5 – 5 + RB =0
-2,5 + RB = 0
RB = 2,5 ton
2.Menghitung Momen
MA = MB = 0 t.m
MC = RA.5
MC = 2,5 . (5)
MC = 12,5 t.m
3. Gaya Lintang
Pada titik A, bekerja RA, Maka DA = RA = 2,5 t
Dari A ke C tidak ada gaya maka nilai D sampai C adalah sama dengan DA.
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